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# Solutions

Discussion in '2: Direct and Inverse Proportions' started by ascklee, Jan 7, 2012.

Solutions

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2. ### Pradeep KumarNew Member

exercise 2F
Page 67
Question No: 5
Given That B2 is inversely proportional to A+3 and B is always positive, find the value of B when A =17
if B=5 when A=2
3. ### Arnold K H TanNew Member

Am assuming your B2 means the square of b, which is represented typed out as: b^2 (just as 5^3 = 125)
Solution:
(B^2)(A+3) = k (k: constant value)
Subst. A = 2 and B = 5 into the equation:
(5^2)(2+3) = k
(25)(5) = k
125 = k
thus, (B^2)(A+3) = 125 is the equation relating variables A and B

When A = 17,
(B^2) (17+3) = 125
B^2 = 125/20 = 25/4
B = sq.rt(25/4)
= 5/2 (note that if this were additional mathematics, the answer must be expressed as +/- 5/2)
= 2.5 (or 2 1/2)
irenequah likes this.
4. ### yumnaghazalNew Member

we need exercise 2d complete
5. ### ZahraNew Member

we need EXCERISE 2D complete 